"Fraction" PPT courseware Simple campus recruitment activity planning plan summary enterprise and institution recruitment publicity lecture PPT template is a general PPT template for business post competition provided by the manuscript PPT, simple campus recruitment activity planning plan summary enterprise and institution recruitment promotion Lecture PPT template, you can edit and modify the text and pictures in the source file by downloading the source file. If you want more exquisite business PPT templates, you can come to grid resource. Doug resource PPT, massive PPT template slide material download, we only make high-quality PPT templates!
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"Fraction" PPT courseware
Monomial: the product of a number and a letter or a letter and a letter
Polynomial: the sum of several monomials
Note: Algebraic expressions include integers, which means that integers are algebraic expressions but algebraic expressions are not necessarily integers.
annotation:
(1) The fraction is also an algebraic expression;
(2) A fraction is the quotient of two integers, and its form is A/B (where A and B are both integers and B is also required to be an integer containing letters)
(3) A is called the numerator of the fraction, and B is the denominator of the fraction.
Note: The values of letters in the fraction cannot make the denominator equal to zero. Because when the value of the denominator is zero, the fraction is meaningless.
Do it
(1) When a=1,2, find the value of the fraction a+1/2a respectively.
(2) When a takes what value, the fraction a+1/2a is meaningless?
(3) When a takes what value, does the fraction a+1/2a make sense?
(4) When a takes what value, the value of the fraction a+1/2a is zero?
Two people A and B start from somewhere on a highway and go in the same direction. It is known that A travels a kilometers per hour, B travels b kilometers per hour, a>b. If B sets off 1 hour ahead of schedule, how long will it take for A to catch up with B? When a=6, b=5, find the time required for A to catch up with B?
Solution: According to the meaning of the question, the distance traveled by B for one hour is 1 × b (kilometers). A travels (a-b) kilometers further per hour than B. Therefore, the time required for A to catch up with B is
b÷(a-b)=b/a-b(hour)
When a=6, b=5, the time required for A to catch up with B is b/a-b=5/6-5=5
Answer: When A needs b/a-b to catch up with B. When a=6, b=5, it takes 5 hours for A to catch up with B.
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