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People's Education Press First Grade Mathematics Volume 1
People's Education Press Second Grade Mathematics Volume 1
Beijing Normal University Edition Seventh Grade Mathematics Volume 2
People's Education Press Third Grade Mathematics Volume 1
Beijing Normal University Edition Eighth Grade Mathematics Volume 1
Qingdao Edition Seventh Grade Mathematics Volume 1
Hebei Education Edition Seventh Grade Mathematics Volume 2
Beijing Normal University Edition Fifth Grade Mathematics Volume 1
Hebei Education Edition Third Grade Mathematics Volume 1
People's Education High School Mathematics Edition B Compulsory Course 2
Qingdao Edition Seventh Grade Mathematics Volume 2
Hebei Education Edition Fourth Grade Mathematics Volume 2
Beijing Normal University Edition Fifth Grade Mathematics Volume 2
People's Education Press First Grade Mathematics Volume 2
Category | Format | Size |
---|---|---|
People's Education Press Eighth Grade Mathematics Volume 1 | pptx | 6 MB |
Description
"Fraction" PPT courseware
Monomial: the product of a number and a letter or a letter and a letter
Polynomial: the sum of several monomials
Note: Algebraic expressions include integers, which means that integers are algebraic expressions but algebraic expressions are not necessarily integers.
annotation:
(1) The fraction is also an algebraic expression;
(2) A fraction is the quotient of two integers, and its form is A/B (where A and B are both integers and B is also required to be an integer containing letters)
(3) A is called the numerator of the fraction, and B is the denominator of the fraction.
Note: The values of letters in the fraction cannot make the denominator equal to zero. Because when the value of the denominator is zero, the fraction is meaningless.
Do it
(1) When a=1,2, find the value of the fraction a+1/2a respectively.
(2) When a takes what value, the fraction a+1/2a is meaningless?
(3) When a takes what value, does the fraction a+1/2a make sense?
(4) When a takes what value, the value of the fraction a+1/2a is zero?
Two people A and B start from somewhere on a highway and go in the same direction. It is known that A travels a kilometers per hour, B travels b kilometers per hour, a>b. If B sets off 1 hour ahead of schedule, how long will it take for A to catch up with B? When a=6, b=5, find the time required for A to catch up with B?
Solution: According to the meaning of the question, the distance traveled by B for one hour is 1 × b (kilometers). A travels (a-b) kilometers further per hour than B. Therefore, the time required for A to catch up with B is
b÷(a-b)=b/a-b(hour)
When a=6, b=5, the time required for A to catch up with B is b/a-b=5/6-5=5
Answer: When A needs b/a-b to catch up with B. When a=6, b=5, it takes 5 hours for A to catch up with B.
Keywords: Fraction courseware, New People's Education Edition eighth grade mathematics PPT courseware, eighth grade mathematics slide courseware download, fraction PPT courseware download, .ppt format
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"Applications of Fractional Equations" PPT courseware 3:
"Applications of Fractional Equations" PPT Courseware 3 Review Review 1. Concept of fractional equations An equation containing an unknown number in the denominator is called a fractional equation. 2. Problem-solving ideas for solving fractional equations 3. Problem-solving steps for solving fractional equations Learning objectives: 1. Be able to analyze the meaning of the problem and find equivalent quantities..
"Applications of Fractional Equations" PPT courseware 2:
"Application of Fractional Equations" PPT Courseware 2 Quote: A and B are making certain machine parts. It is known that A makes 6 more parts per hour than B. The time it takes A to make 90 parts is the same as the time it takes B to make 60 parts. If the time is equal, how many parts can A and B each make per hour? equal amount..
"Applications of Fractional Equations" PPT courseware:
Summary of the "Applications of Fractional Equations" PPT courseware: Steps and methods for solving application problems with column fraction equations: 1. Review, set up, list, solve, test, and answer 2. Find equivalent relationships Summary Summary of solving column fraction equations General steps and precautions for application questions: (1) Question review:..
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Update Time: 2024-10-31
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