"Encounter Problems" Four Mixed Operations PPT Courseware

Description

"Encounter Problems" Four Mixed Operations PPT Courseware

teaching objectives

1. Combined with specific examples, go through the process of discussion, independent answer to "encounter" questions and exchange of algorithms.

2. Understand the quantitative relationship of encounter problems, be able to answer simple encounter problems, and express one's own ideas.

3. Experience the process of communicating various algorithms with others, experience the diversity of problem-solving strategies, and enhance the awareness of mathematical applications.

Calculate the two questions in each set of equations below and tell us what you found?

15×6+85×6＝600

(15+85)×6=600

8×25＋4×25＝300

(8+4)×25＝300

in an equation

Contains only operations of the same level

Calculate from left to right

Contains two levels of operations

Calculate the second-level operation first, then the first-level operation.

Contains parentheses

Calculate what's inside the parentheses first, then what's outside the parentheses.

A passenger bus and a truck drove opposite each other from Beijing and Zhengzhou and met each other after 4 hours. How many kilometers is it between Beijing and Zhengzhou?

① Passenger car speed × meeting time + truck speed × meeting time = distance between the two places

92 × 4 + 80 × 4

= 368 + 320

= 688 (km)

Answer: Beijing and Zhengzhou are 688 kilometers apart.

② (Speed ​​of passenger car + speed of truck) × Encounter time = Distance between the two places

(92 + 80)×4

= 172×5

= 688 (km)

Answer: Beijing and Zhengzhou are 688 kilometers apart.

practice

1. Two cars A and B drove out of the parking lot in opposite directions at the same time. 4. How many kilometers will the two cars be apart after 2 hours?

2. Two rollers roll toward each other from both ends of a section of road at the same time. One moves 65 meters per minute, the other moves 68 meters per minute, and they meet after 12 minutes. How many meters long is this section of road?

(65 + 68)×12

= 133×12

= 1596 (meters)

Answer: This section of road is 1596 meters long.

3. Two engineering teams jointly dug a 690-meter-long canal, each starting from one end at the same time. The first team dug 14.8 meters per day, and the second team dug 15.2 meters per day. How many days will it take to dig this canal?

690÷(14.8 + 15.2)

＝690÷30

= 23 (days)

Answer: It will take 23 days to dig this canal.

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For more information about the PPT courseware "Four Arithmetic Mixed Operations for Encounter Problems", please click the "Four Arithmetic Mixed Operations for Encounter Problems ppt" tab.

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Update Time: 2024-09-08

This template belongs to Mathematics courseware Hebei Education Edition Fifth Grade Mathematics Volume 1 industry PPT template

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