"Application of linear equation of one variable - discount sales" linear equation of one variable PPT

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"Application of linear equations of one variable - discount sales" linear equation of one variable PPT

Part One: Learning Objectives

1. Analyze the quantitative relationship in the problem and establish equations to solve the problem

2. Find equivalence relationships and list equations; solve equations accurately

Applying linear equations of one variable to sell PPT at discounts, part 2: independent learning feedback

1. The price of a product is 50 yuan, and it is now sold at a 20% discount, and the selling price is ____ yuan; if the purchase price is 32 yuan, then his profit is ____ yuan, and the profit margin is ______.

2. The cost price of a watch is 70 yuan, and the profit margin is 30%. Then the profit of this watch is ____ yuan, and the selling price should be ____ yuan.

3. The original price of a mobile phone is 1,080 yuan. Now it is on sale. If the price is 810 yuan, the merchant will sell it at a ______ discount.

Applying the linear equation of one variable to sell PPT at a discount, part three: new knowledge explanation

(1) What’s the deal with the discount?

(2) What is the meaning of 30% off and 20% off?

(3) Rewrite the following "discount" numbers into percentages

10% off: 90%

25% off: 75%

12% off: 88%

concept related to discount sales

(1) Purchase price: The price at which the goods are purchased, that is, the cost price.

(2) Selling price: The selling price when selling goods, that is, the selling price.

(3) Price: The price marked at the time of sale, that is, the original price or the fixed price.

(4) Profit: the net income from selling goods. In the textbook, it is stipulated that profit = selling price - purchase price.

(5) Discount: When selling goods, if you multiply the listed price by a few tenths or a few percent, it is called "a discount based on the listed price."

A store marked a certain piece of clothing at a 40% increase in cost and then sold it at a 20% discount. As a result, each piece still made a profit of 15 yuan. How much does each piece of this kind of clothing cost?

Assume that the cost price of each piece of clothing is x yuan. Can you use an algebraic expression containing x to express other quantities? What is the equivalence relationship in the problem?

The price of each piece of clothing is:____________;

The actual selling price of each piece of clothing is:____________;

The profit per piece of clothing is:____________;

From this, the equation is listed: ____________;

Solving the equation, we get x=____________.

Therefore, the cost price of each piece of clothing is ______ yuan.

Analysis of classic examples

Example: A shopping mall sells a certain product at 20% off the original price. At this time, the profit margin of the product is 10%. It is known that the purchase price of this product is 1,800 yuan, then what is the original price of this product?

Do it

The purchase price of each TV set of a certain brand is 1,200 yuan, and the listed price is 2,500 yuan. In order to promote sales, a certain store stipulates that the TV set be sold at 40% off the listed price. What is the profit from selling this brand of TV set? What is the profit margin?

[Analysis] The profit can be calculated according to "profit = selling price - purchase price"; according to

The profit rate can be found.

Using linear equations to sell PPT at a discount, Part 4: In-class testing

1. The original price of a certain product is 165 yuan per piece. After the price is reduced by 10%, the selling price is ________ yuan.

If the cost is 110 yuan, the profit is ________ yuan.

2. The purchase price of a certain product is 500 yuan, and each item is sold for 750 yuan. The store requires a discount of not less than 5% of the profit, so the product can be sold at a maximum discount of ________.

Analysis: Assume that this product can be sold at a maximum discount of

3. The purchasing price of a certain product is 250 yuan. If it is sold at 10% off the listed price, the profit margin is 15.2%. What is the listed price of the product?

Solution: Suppose the price of the product is x yuan,

Solve to get x=320.

So the price of the product is 320 yuan.

Answer: The price of the product is 320 yuan.

4. The store sells teapots and teacups. Teapots are 24 yuan each and teacups are 5 yuan each. There are two discount methods:

(1) Buy a teapot and get a teacup for free;

(2) Pay at a 10% discount on the original price. A customer bought 5 teapots and x teacups (x≥5).

(1) Calculate the payment numbers y1 and y2 in the two ways (expressed by formulas containing x).

(2) When purchasing how many teacups, the payment amount of the two methods is the same?

Solution: (1) According to the meaning of the question, we get y1=24×5+5(x-5);

y2=90%(24×5+5x).

(2) According to the meaning of the question, we get 24×5+5(x-5)=90%(24×5+5x). Solving the equation, we get x=26.

Answer: When buying 26 teacups, the payment amount for both methods is the same.

5. A product is priced at a 20% increase in cost price and is sold at a 10% discount. The selling price is 270 yuan. What is the cost price of this product?

Solution: Suppose the cost price of this product is x yuan,

According to the question, we get x(1+20%)×0.9=270.

The solution is x=250. So the cost price of this product is 250 yuan

Applying linear equations of one variable to sell PPT at discounts, Part 5: Class summary

1. Understand the basic concepts and equality relationships in commodity sales issues,

Skillfully apply "profit = selling price - cost price"

"Profit rate = profit ÷ cost price × 100%"

to find the equivalence relationship in product sales.

2. Connect with previously studied issues and deepen your understanding using one yuan per square

General steps for solving practical problems.

Analysis ① Known conditions Unknown conditions ② Equivalent relationship

Answer ①Assume ②Column ③Solution ④Verify ⑤Answer

Applying linear equations to sell PPT at discounts, Part 5: Personalized assignments

1. Complete the after-school homework of Group A in 5.4 Applying linear equations in one variable to sell discounts.

2. Preview pages 149-150 of the textbook and complete the independent learning test questions in the next section.

1. Complete the after-school homework of Group B in 5.4 Applying linear equations in one variable to sell discounts.

2. Preview pages 149-150 of the textbook and complete the independent learning test questions in the next section.

Keywords: Beijing Normal University Edition seventh-grade mathematics PPT courseware free download, application of linear equations of one variable discount sales PPT download, linear equations of one variable PPT download, .PPT format;

For more information about the PPT courseware "Linear Equations of One Variable and Applying Linear Equations of One Variable to Discounted Sales", please click the PPT Discounted Sales of Linear Equations of One Variable and Applying Linear Equations of One Variable PPT tag.

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Update Time: 2024-11-08

This template belongs to Mathematics courseware Beijing Normal University Edition Seventh Grade Mathematics Volume 1 industry PPT template

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