"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2)

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"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2)

Part One Content: Basic Knowledge Key Points

Knowledge point 1: Use bracket removal to solve linear equations of one variable

1. Remove the brackets from the equation 2x-4(2x-3)=6-2(x+1). The correct one is (D)

A.2x-8x-12=6-2x+2

B.2x-8x+12=6-2x+1

C.2x-8x+3=6-2x-2

D.2x-8x+12=6-2x-2

2. (Adapted) Solve equation 4(x-1)-x=2(x+1/2), the steps are as follows:

①Remove the brackets, get 4x-4-x=2x+1; ②Move the terms, get 4x+x-2x=4+1; ③Combine similar terms, get 3x=5; ④Change the coefficient to 1, get x=5 /3. The step where errors begin is (B)

A.① B.② C.③ D.④

3. The solution of equation 3x+2(1-x)=4 is x=2.

4. Solve the following equations:

(1)1+3(x-2)=4;

(2)5(2-x)=-(2x-7);

(3)3(3x+1)=2(5x-3)+6;

( 4 )8x+4=2( 4x+3 )-2( 1-3x ).

Knowledge point 2: Application of removing brackets to solve linear equations of one variable

5. There are 35 students in a certain class. The number of people who join the literary club is three times the number of people who join the scientific club. There are 3 people who participate in both the literary club and the scientific club. There are 2 people who join neither the literary club nor the scientific club. Then the number of people who join the science club but not the literary club is (D)

A.3 B.4 C.5 D.6

6. In the "I Love the Motherland" essay competition held in Hongcheng Middle School, the seventh and eighth graders received a total of 118 essays, and the number of essays received by the eighth grade was twice that of the seventh grade. If there is one more essay, how many essays will the eighth graders receive?

Solving linear equations of one variable PPT, part 2: improvement of comprehensive abilities

9. If (5x+2) and (-2x+7) are opposites of each other, then the value of 2-x is (C)

A.-1 B.1 C.5 D.-5

10. (Original) In the trapezoid area formula S=1/2(a+b)h, it is known that S=48, h=12, b=6, then the value of a is (D)

A.8 B.6

C.4 D.2

11. If 3/2ab2(n-1) and -abn+1 are similar terms, then the value of n is 3.

12. If m = x + 3, n = 2 - x, then when x = 2, the value of m is 5 times greater than the value of n.

13. Solve the equation: 5( 3-2x )-4( 5+3x )=2( 20-18x )-17.

Student Ma Xiaohu’s solution is as follows:

Remove the brackets and you get 15-10x-20+12x=40-36x-17.

Moving the items, we get -10x+12x+36x=40-17-15-20.

Combining similar terms, we get 38x=-12.

Divide both sides of the equation by 38 to get x=-6/19.

Solving linear equations of one variable PPT, the third part: Expanding exploration and breakthroughs

18. In order to investigate the parking situation in the parking lot, the owner of the parking lot asked: "Xiao Zhang, how many cars were parked today? How much was the charge?" Xiao Zhang replied: "Boss, there were 50 cars parked in the parking lot today, a total of 50 cars. The charge was 340 yuan." The boss asked again: "Medium-sized cars are charged 8 yuan each, and small cars are charged 5 yuan each. How many small cars are parked? How many medium-sized cars are parked?"

Based on the conversation above, do you know how many small cars are parked in this parking lot? What about medium-sized cars?

Solution: Suppose x number of medium-sized cars are parked, then (50-x) number of small cars are parked. According to the meaning of the question, we get 8x+5(50-x)=340, and the solution is x=30.

So 50-x=20.

Answer: 30 medium-sized cars were parked, and 20 small cars were parked.

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For more information about the PPT courseware "Solving a linear equation of one variable using a linear equation of one variable", please click the PPT tag of Solving a linear equation of one variable using a linear equation PPT.

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Update Time: 2024-11-19

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