"Understanding linear equations of one variable" PPT download of linear equations of one variable (Lesson 1)

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"Understanding linear equations of one variable" PPT download of linear equations of one variable (Lesson 1)

Part One Content: Basic Knowledge Key Points

Knowledge point 1: Definition of linear equation of one variable

1. Which of the following equations is a linear equation of one variable (D)

A.2x-y=0 B.x2-x=1

C.xy-3=5 D.x+1=2

2. (Original) It is known that the equation (a-2)x|a|-1+7=0 is a linear equation of one variable with respect to x, then the value of a is (B)

A.2 B.-2 C.±2 D. Unable to determine

Knowledge point 2: Column equations

3. Li Hong bought 8 lotus pods, paid 50 yuan, and got 38 yuan back. Assuming the price of each lotus pod is x yuan, the equation that can be listed according to the meaning of the question is 50-8x=38.

4. Make an equation based on the following conditions:

(1) A certain number is 5 times smaller than its 3 times;

(2) 2/3 of a certain number is 25 more than 20% of the number.

Understanding linear equations of one variable PPT, part 2: improvement of comprehensive abilities

9. A certain village originally had 120 hectares of forest land and 50 hectares of dry land. In order to adapt to the adjustment of industrial structure, part of the dry land needs to be transformed into forest land. After the transformation, the dry land area accounts for 10% of the forest land area. Suppose x hectares of dry land are transformed into forest land, then The correct equation listed is (A)

A.50-x=10%( 120+x )

B.50+x=10%×120

C.170-x=10%(50+x)

D.50-x=10%×120

11. (Original) For rational numbers a and b, a new operation is defined: a*b=ab+b. For example, 2*3=2×3+3=9. The following conclusions are reached: ①( -3 )*4 =-8;②a*b=b*a;③x=5 is the solution of equation (x-4)*3=6; ④(4*3)*2=32. The correct conclusion is ①③④.(Fill in the serial number )

12. It is known that the equation (2m-4)x2+x3n-5-8=0 is a linear equation of one variable with respect to x. Find the values ​​of m and n.

Understanding the linear equation of one variable PPT, the third part of the content: Expanding the exploration and breakthrough

13. Knowing that 3am+1b2 and 5a3bn-1 are similar terms, try to judge whether x=(m−n)/2 is the solution to equation 2x-5=0?

Solution: From the definition of similar terms, we know that m+1=3, n-1=2.

So m=2,n=3. So x=(2"-" 3)/2=-1/2.

Because when x=-1/2, 2x-5=2×("-" 1/2)-5=-6≠0, so x=(m"-" n)/2 is not the equation 2x-5= Solution to 0.

Keywords: Beijing Normal University edition seventh-grade mathematics PPT courseware free download, understanding of linear equations of one variable PPT download, linear equations of one variable PPT download, .PPT format;

For more information about the PPT courseware "Linear Equations of One Variable and Understanding the Linear Equations of One Variable", please click on the PPT "Linear Equations of One Variable" PPT and Understanding the Linear Equations of One Variable PPT tag.

"Understanding linear equations of one variable" PPT download of linear equations of one variable (Lesson 2):

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"Understanding linear equations of one variable" PPT courseware of linear equations of one variable (Lesson 2):

"Understanding linear equations of one variable" PPT courseware of linear equations of one variable (Lesson 2) Part 1: Learning objectives 1. Understand the basic properties of equations. (Key points) 2. Be able to use the properties of equations to solve simple linear equations of one variable. (Difficulty points )... ... ... Get to know Yiyuanyi..

"Understanding linear equations of one variable" PPT courseware of linear equations of one variable (Lesson 1):

"Understanding linear equations of one variable" PPT courseware of linear equations of one variable (Lesson 1) Part 1: Learning objectives 1. Understand the concept of linear equations of one variable. 2. Be able to list linear equations of one variable based on the equivalent relationships in specific problems. (Key points , difficulty) ... ... ... ... ..

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Update Time: 2024-11-21

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