"Application of linear equations of one variable - the water tank becomes higher" PPT courseware download of linear equations of one variable

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"Application of linear equations of one variable - the water tank becomes higher" PPT courseware download of linear equations of one variable

Part One Content: Basic Knowledge Key Points

Knowledge point 1: Volume equation based on three-dimensional figures

1. The volume of a cylinder with a diameter of 80 mm and a height of 60 mm is 5 times the volume of a cylinder with a diameter of 40 mm and a height of x(mm). Then the correct equation listed is (A)

2. A certain steel ingot has a square cross-section with a side length of 40 cm. If it is to be forged into a rectangular parallelepiped with length, width, and height of 50 cm, 20 cm, and 10 cm respectively, the length of the steel ingot should be 6.25 cm.

3. A cylindrical bottle with an inner diameter of 30 cm at the base and a height of 30 cm is filled with a drink. The drink is poured into a small cylindrical cup with an inner diameter of 10 cm at the base. 20 cups are exactly filled. Find the small cup. height of.

Solution: Let the height of the small cup be x cm. According to the meaning of the question, we get

π×152×30=20x×π×52, the solution is x=13.5.

Answer: The height of the small cup is 13.5 cm.

Knowledge point 2: Formulate equations based on the perimeter and area of ​​plane figures

4. It is necessary to build a rectangular green space with a perimeter of 140 m, and the length is 10 m longer than the width. Let the width of the green space be x m. According to the meaning of the question, the correct equation listed below is (D)

A.2(x-10)=140

B.2[x+"( "x"−" 10" )" ]=140

C.2(x+10)=140

D.2[x+"( "x+10" )" ]=140

5. (Adapted) Use a 40 cm long iron wire to form a rectangle with a length-to-width ratio of 3:1, then the area of ​​the rectangle is (C)

A.50 cm2 B.70 cm2

C.75 cm2 D.120 cm2

6. As shown in the figure, a large rectangle with a width of 50 cm is made up of 10 congruent small rectangles. Find the area of ​​the small rectangle.

Applying the linear equation of one variable to increase the height of the water tank PPT, part two: improvement of comprehensive capabilities

8. As shown in the figure, a rectangular shade cloth with a width of 1 m is nailed to a rectangular window with a perimeter of 10 m, so that the light-transmitting part is exactly a square, then the light-transmitting area after nailing is (A)

A.4 m2 B.9 m2 C.16 m2 D.25 m2

9. There are two types of paper cups of different sizes and two barrels of juice A and B. The volume ratio of the small paper cup to the large paper cup is 2:3, and the volume ratio of the juice in barrel A to the juice in barrel B is 4:5. If the volume ratio in barrel A is The juice just fills 120 small paper cups, then the maximum number of large paper cups that the juice in bucket B can fill is (B)

A.64 B.100 C.144 D.225

10. It is known that the height of a trapezoid is 8 cm, the length of the upper base is 14 cm, and the length of the lower base is 6 cm less than twice the length of the upper base. Now change this trapezoid into a rectangle equal to its area. If one side of the rectangle is long is 6 cm, then the perimeter of the rectangle is 60 cm.

Using a linear equation of one variable to make the water tank taller PPT, part three: Expanding exploration and breakthroughs

16. As shown in the figure is a rectangular color block diagram that appears on the computer screen, consisting of 6 squares of different colors. Assume that the side length of the smallest square in the middle is 1, and find the area of ​​this rectangular color block diagram.

Solution: Suppose the side lengths of the two equal squares in the lower right corner are x, then the side lengths of the remaining three squares in the clockwise direction are x+1, x+2, x+3.

According to the meaning of the question, we get x+x+( x+1 )=( x+2 )+( x+3 ),

Solve to get x=4.

So (x+2)+(x+3)=13,(x+2)+(x+1)=11,

Then the area of ​​the rectangle is 13×11=143.

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For more information about the PPT courseware "The water tank has become higher by applying the linear equation of one variable to the linear equation of one variable", please click the PPT tag of "The water tank has become higher by applying the linear equation of one variable" PPT.

"Application of linear equations of one variable - the water tank becomes higher" PPT teaching courseware of linear equations of one variable:

"Application of linear equations of one variable makes the water tank higher" PPT teaching courseware for linear equations of one variable Part one content: Teaching objectives 1. Find the invariants in the problem by analyzing practical problems; 2. Be able to find equivalent relationships based on the invariants; 3. Suppose the unknowns are based on the equivalence relationship,...

"Application of linear equation of one variable - the water tank becomes higher" PPT download of linear equation of one variable:

"The water tank becomes taller by applying linear equations of one variable" PPT download of linear equations of one variable Part one content: Learning objectives 1. Learn to analyze quantitative relationships and equivalent relationships in complex problems with the help of three-dimensional and plane graphics. (Difficulty) 2. Be able to use linear equations of one variable Equations are easy to solve...

"Application of linear equation of one variable - the water tank becomes higher" PPT of linear equation of one variable:

"The water tank becomes taller by applying linear equations of one variable" PPT of linear equations Part 1: Learning objectives 1. Establish equations to solve problems by analyzing the basic equivalent relationships in graphic problems. 2. Learn more about the application of linear equations of one variable in solving practical problems.

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Update Time: 2024-09-27

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