"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 3)

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"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 3)

Part One Content: Basic Knowledge Key Points

Knowledge point 1: Remove the denominator

1. Remove the denominator from the equation x-(x"-" 1)/2=2-(x+2)/5. The correct one is (B)

A.10x-5( x-1 )=2-2( x+2 )

B.10x-5( x-1 )=20-2( x+2 )

C.10x-5( x-1 )=20-( x+2 )

D.10x-( x-1 )=2-2( x+2 )

2. Remove the denominator from the equation (2x"-" 1)/3-(x"-" 1)/4=1 to get 8x-4-3x+3=1, this deformation (B)

A. The lowest common multiple of the denominator is wrong.

B. Missing multiplication terms without denominators

C. The polynomial in the numerator is not bracketed and has the wrong symbol.

D.Correct

Knowledge point 2: Use the denominator to solve linear equations of one variable

3. The solution of the equation x/4=(x- 1)/5 is (D)

A.x=4 B.x=1

C.x=-1 D.x=-4

4. The steps to solve the equation (x"-" 1)/3-(x+2)/6=(4"-" x)/2 are as follows. The error occurs in the step ②.

Solving linear equations of one variable PPT, part 2: improvement of comprehensive abilities

8. There are the following deformations: ① Remove the denominator from the equation (x"-" 12)/5=2, and get x-12=10; ② Divide both sides of the equation 2/9x=2/9 by 2/9, and get x =1; ③ By moving the terms of equation 6x-4=x+4, we get 7x=0; ④ By multiplying both sides of equation 2-(x"-" 5)/6=(x+3)/2 by 6, we get 12-x-5=3(x+3).The number of error deformations is (C)

A.4 B.3 C.2 D.1

9. Transform the equation (x+4)/(0"." 2)-(x"-" 3)/(0"." 5)=2. The correct result is (D)

A.(x+4)/2-(x"-" 3)/5=2

B.(x+4)/2-(x"-" 3)/5=20

C.10(x+4)/2-10(x"-" 3)/5=20

D.5( x+4 )-2( x-3 )=2

10. It is known that the solution of equation 3x-m=(m+3x)/2 is the same as equation 2(x+2)=4(x+3), then the value of m is (C)

A.-18 B.18 C.-4 D.-12

11. If the value of the algebraic formula (k+1)/3 is 1 less than the value of (3k+1)/2, then the value of k is (D)

A.-1 B.2/7 C.1 D.5/7

12. Solve the equation 5/6 (6/5 x"-" 1)=2. The simpler of the following solutions is (C)

A. First multiply both sides by 6 B. First multiply both sides by 5

C. Remove the brackets first and then move the items. D. Make the points inside the brackets first.

Solving linear equations of one variable PPT, the third part: Expanding exploration and breakthroughs

17. It is known that (a+b)y2-y^(1/3 a+2)+5=0 is a linear equation of one variable about y.

(1) Find the values ​​of a and b;

(2) If x=a is the solution of the equation (x+2)/6-(x"-" 1)/2+3=x-(2x"-" m)/6, find |a- The value of b|-|b-m|.

Solution: (1) From the question, we know that a+b=0, 1/3a+2=1,

Solve to get a=-3,b=3.

(2) Substituting x=a=-3 into the equation (x+2)/6-(x"-" 1)/2+3=x-(2x"-" m)/6, the solution is m=41.

So |a-b|-|b-m|=|-3-3|-|3-41|=-32.

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For more information about the PPT courseware "Solving a linear equation of one variable using a linear equation of one variable", please click the PPT tag of Solving a linear equation of one variable using a linear equation PPT.

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Update Time: 2024-07-05

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