"Application of linear equations of one variable - chasing Xiao Ming" PPT courseware download of linear equations of one variable

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"Application of linear equations of one variable - chasing Xiao Ming" PPT courseware download of linear equations of one variable

Part One Content: Basic Knowledge Key Points

Knowledge point 1: Opposite encounter problem

1. The distance between stations A and B is 335 km. A local train runs from station A to station B, traveling 55 km per hour. After the local train travels for 1 hour, another express train runs from station B to station A, traveling 55 km per hour. Traveling 85 km. Assume that the express train meets the slow train after traveling for x hours, then the equation can be written as (D)

A.55x+85x=335

B.55(x-1)+85x=335

C.55x+85(x-1)=335

D.55(x+1)+85x=335

2. Xiao Zhang and Xiao Li set off from A and B at the same time. Xiao Zhang rode a bike and Xiao Li walked, walking towards each other at a constant speed along the same straight route. They met 2.5 hours after starting, and Xiao Li left again after meeting. 9 km to reach the midpoint of A and B, and Xiao Zhang arrives at B 0.5 h after the encounter, then Xiao Zhang’s traveling speed is 9 km/h.

Knowledge point 2: Follow up on the problem

3. Xiaogang and Xiaoqiang practice running. Xiaogang runs 7 meters per second and Xiaoqiang runs 6.5 meters per second. Xiaogang asks Xiaoqiang to run 5 meters first. Assume that Xiaogang catches up with Xiaoqiang after x seconds. The following four The incorrect part of the equation is (B)

A.7x=6.5x+5 B.7x-5=6.5

C.(7-6.5)x=5 D.6.5x=7x-5

Apply linear equations of one variable to catch up with Xiao Ming’s PPT, part 2: improvement of comprehensive capabilities

8. A ship sails between two docks A and B. It takes 3 hours to sail along the current and 5 hours to sail against the current. It is known that the water speed is 4 km/h. Find the sailing speed of the ship in still water. If the ship The sailing speed in still water is x km/h, then the equation can be written as (C)

A.3x+4=5x-4

B.3( 4+x )=5( 4-x )

C.3( x+4 )=5( x-4 )

D.3( x-4 )=5( x+4 )

9. (Taizhou High School Entrance Examination) Didi Express is a convenient travel tool. The pricing rules are as follows:

Xiao Wang and Xiao Zhang each took Didi Express, and their driving distances were 6 kilometers and 8.5 kilometers respectively. If they paid the same fare when they got off the train, then the travel time difference between the two Didi Express trains is (D)

A.13 minutes B.15 minutes

C.18 minutes D.19 minutes

10. According to the "Thirteenth Five-Year Plan" railway plan of a certain province, after the completion of the passenger dedicated line project from point A to point B, the shortest passenger transportation time from point A to point B will be shortened from the current 2 hours and 18 minutes to 36 minutes, and its speed will be Increase the speed by 260 kilometers, and find the train speed after the increase. (Accurate to 1 km/h)

Solution: Let the increased train speed be x kilometers/hour.

According to the meaning of the question, we get 0.6x=2.3(x-260), and the solution is x≈352.

Answer: The increased train speed will be approximately 352 kilometers/hour.

Using linear equations of one variable to catch up with Xiao Ming’s PPT, the third part: Expanding exploration and breakthroughs

14. There are two boats, A and B, in a straight river. They are moving down the river from point A at the same time. When boat B arrives at point B, it receives a notification and immediately goes upstream and returns to point C to perform its task. Boat A continues to flow downstream. Navigation. It is known that the speeds of ships A and B in still water are both 7.5 km/h, the water speed is 2.5 km/h, and the distance between A and C is 10 km. If ship B travels from A to B It took 4 hours to arrive at point C. Question: When ship B arrives at point C from point B, how far is ship A from point B?

Solution: Suppose it takes x h for ship B to sail from place B to place C. Then it takes (4-x)h for both ships A and B to sail from place A to place B.

(1) If land C is between land A and land B, then the distance from land A to land B is (7.5+2.5)(4-x)km, and the distance from land B to land C is (7.5-2.5)x km.

According to the distance from A to B - the distance from B to C = the distance between A and C, we get (7.5+2.5)(4-x)-(7.5-2.5)x=10,

After sorting, we get 10(4-x)-5x=10, and we get x=2.

Therefore, ship A is (7.5+2.5)×2=20 km away from point B.

Keywords: Beijing Normal University Edition seventh-grade mathematics PPT courseware free download, application of linear equations of one variable to catch up with Xiao Ming PPT download, linear equations of one variable PPT download, .PPT format;

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Update Time: 2024-08-05

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