"Simple Calculation Using Chemical Equations" Chemical Equations PPT Courseware 5

Description

"Simple Calculation Using Chemical Equations" Chemical Equations PPT Courseware 5

learning target

1. On the basis of understanding the meaning of chemical equations, master the calculation of the quantities of reactants and products.

2. Through the calculation of chemical equations, master the writing format of chemical equation calculations, and at the same time cultivate and improve thinking and problem-solving abilities.

Learning points

1. Master the mass of a known reactant (or product) and find the mass of the product (or reactant).

2. Standardize the writing format calculated based on chemical equations.

What is the significance of chemical equations? (Take the decomposition of potassium permanganate as an example)

2KMnO4=== K2MnO4 + MnO2 + O2

This shows that in a chemical reaction, the mass ratio between reactants and products is directly proportional. Therefore, using the direct proportional relationship according to the chemical equation and the known mass of a reactant (or product), the mass of the product (or reactant) can be found.

1. Indicates that potassium permanganate decomposes when heated to generate potassium manganate, manganese dioxide and oxygen.

2. Indicates that every 316 parts by mass of potassium permanganate reacts completely to produce 197 parts by mass of potassium manganate, 87 parts by mass of manganese dioxide and 32 parts by mass of oxygen.

Three essentials and three keys to calculation based on chemical equations

Three essentials:

(1) The steps must be complete (assume, write, calculate, label, list, solve, and answer)

(2) The format must be standardized

(3) The number must be accurate (retain two decimal places)

Three keys:

(1) Write chemical equations accurately

(2) Accurately calculate relative molecular mass

(3) The substitution amount refers to the mass of the pure substance (the unit must be substituted into the calculation process)

1. Please tell the meaning of 2KClO3 = 2KCl+ 3O2↑.

2. When 490g of potassium chlorate is heated, how much oxygen can be produced at most?

3. Place 6g of the mixture of pure potassium chlorate and manganese dioxide in a test tube and heat it until gas no longer is produced. The mass of the remaining solid is 4.04g.

(1) How many grams of oxygen are produced in the reaction?

(2) How many grams of potassium chlorate are in the original mixture?

(3) How many grams of each substance is contained in the remaining solid after heating?

4. There is a 10g hydrogen peroxide sample containing water. Under the catalytic action of manganese dioxide, it is completely decomposed to obtain 3.2g of oxygen. What is the mass fraction of hydrogen peroxide in the hydrogen peroxide sample?

5. In reaction 4A+3B==2C, if 2.7gA reacts completely to produce 5.1g of C. It is known that the relative molecular mass of B is 32, then the relative molecular mass of C is ( )

A. 34 B. 68 C. 102 D. 204

summary:

Calculation requirements based on chemical equations:

Chemical equations need to be balanced

It is necessary to substitute the scalar equation into

relational expression to relational quantity

Don’t forget the calculation unit

Proportional relationship between quantities

It is better to remember the solution than the answer

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For more information about the "Chemical Equations Simple Calculations Using Chemical Equations" PPT courseware, please click on the Chemical Equations ppt Simple Calculations Using Chemical Equations ppt tag.

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Update Time: 2024-06-12

This template belongs to Chemistry courseware People's Education Press Ninth Grade Chemistry Volume 1 industry PPT template

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