"Application of Quadratic Functions" PPT download

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"Application of Quadratic Functions" PPT download

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"Application of Quadratic Functions" PPT download

Part One: Situational Issues

A certain large grain farmer planted 360 acres of high-quality rice last year and plans to rent an additional X (100 ≤ (440-2x) yuan, let me ask: How many acres of rice should this large grain farmer increase in renting this year to maximize the total income? What is the maximum income?

Give it a try:

Find the maximum value of the quadratic function y=-100x2+100x+200?

A store sells a certain product, and it is known that the unit price is 8 yuan when purchased in batches. According to market research, sales volume and sales unit price satisfy the following relationship: within a period of time, when the unit price is 10 yuan, the sales volume per day is 100 pieces, and every time the unit price decreases by 0.1 yuan, 10 more pieces can be sold. Could you please help me analyze how much the unit sales price can be reduced to achieve the maximum profit every day?

Discuss:

Find the maximum value of the quadratic function y=x(20-2x)?

It is necessary to use a 20m long iron railing with one side against the wall to form a rectangular garden. How to enclose it to maximize the area of ​​the enclosed garden?

Attachment: If the length of the side of the flowerbed perpendicular to the wall is xm and the area of ​​the flowerbed is ym2, then y=x(20-2x)

Application of quadratic functions PPT, part 2: learn to generalize

What are the general steps to use the properties of quadratic functions to solve many optimal value problems in real life?

(1) List the analytical formula of the quadratic function, and determine the value range of the independent variables based on the actual meaning of the independent variables;

(2) Within the value range of the independent variable, use the formula method or formula to find the maximum or minimum value of the quadratic function.

Application of quadratic functions PPT, the third part: Selected practice questions for the high school entrance examination

The cost of each product of a product is 10 yuan. The relationship between the sales price x (yuan) of each product in the trial marketing stage and the daily sales volume y (pieces) of the product is as follows:

If the daily sales volume y is a linear function of the sales price x.

(1) Find the functional relationship between daily sales volume y (pieces) and sales price x (yuan); (6 points)

(2) To maximize daily sales profits, how much should the sales price of each product be? How much is the daily sales profit at this time? (6 points)

Tip: Daily profit = (sales price - cost) × sales volume

Keywords: Free download of Hebei Education Edition mathematics PPT courseware for the second volume of ninth grade, application of quadratic functions PPT download, .PPT format;

For more information about the "Applications of Quadratic Functions" PPT courseware, please click on the "Applications of Quadratic Functions" ppt tab.

"Applications of Quadratic Functions" PPT free download:

"Application of Quadratic Function" PPT free download Part 1 content: Learning objectives 1. Experience the process of exploring the maximum profit in the T-shirt sales process, realize that the quadratic function is a mathematical model of a type of optimization problem, and experience the application of mathematics Value. 2. Master the reality..

"Applications of Quadratic Functions" PPT courseware download:

"Applications of Quadratic Functions" PPT courseware download part one content: Learning objectives 1. Let students become more familiar with the transformation between point coordinates and line segments. 2. Let students learn to use the knowledge of quadratic functions to solve related practical problems. 3 .Master the idea of ​​mathematical modeling and experience...

"Applications of Quadratic Functions" PPT:

"Applications of Quadratic Functions" PPT Part 1 Content: Review and think about whether the graph of the quadratic function intersects with the x-axis, and what determines it? The symbol of b-4ac determines b-4ac�0, and there are two intersection points b- 4ac=0, there is only one intersection point b-4ac�0, there is no intersection point..

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Update Time: 2024-11-22

This template belongs to Mathematics courseware Hebei Education Edition Ninth Grade Mathematics Volume 2 industry PPT template

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