"Properties of Angle Bisectors" PPT Courseware 2

"Properties of Angle Bisectors" PPT Courseware 2
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"Properties of Angle Bisectors" PPT Courseware 2

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"Properties of Angle Bisectors" PPT Courseware 2

As shown in the figure, it is an instrument that bisects an angle. AB=AD, CB=CD. Place point A at the vertex of the angle. Place AB and AD along both sides of the angle. Draw a ray AE along AC. AE is the bisector of the angle. Wire. Can you make sense of it?

According to SSS, we know that two triangles are congruent

∴∠1=∠2

From the above exploration, can you figure out how to construct the angle bisector of an angle?

Known: ∠AOB

Find: bisector of ∠AOB

Method: (1) Take O as the center of the circle, draw an arc with an appropriate length as the radius, intersect OA at M, and intersect OB at N;

(2) Take M and N as the center of the circle respectively, and draw an arc with a length greater than 1/2MN as the radius. The two arcs intersect at point C inside ∠AOB.

(3) Make ray OC. Ray OC is what you want.

Can you explain why?

Do the exercises on page P108 and answer the questions.

Do it

1. Can you fold the bisector of an angle?

Fold ∠AOB in half

2. Then fold a right triangle (make the angle bisector the hypotenuse, OA and OB the right-angled sides)

What conclusion can you draw by observing the three creases made by two folds?

The two creases made the second time are equal in length.

Can you explain why?

What conclusion can you draw from the above experiment?

Example 1 Known: As shown in the figure, E is a point on the bisector of ∠BAC, EB⊥AB,

EC⊥AC, B, and C are vertical feet respectively. Prove: ∠EBC=∠ECB

Prove: ∵ E is a point on the bisector of ∠BAC, EB⊥AB, EC⊥AC

∴EB=EC

(A point on the bisector of an angle is equidistant from both sides of the angle)

∴∠EBC=∠ECB (in a triangle, equal sides correspond to equal angles)

Think about it: Is BC in the question bisected perpendicularly by AE?

∵∠ABE=∠ACE=Rt∠

∠1=∠ 2∴∠3=∠4

Also ∵EB=EC

∴ AE bisects BC perpendicularly

Summary:

1 A point on the bisector of an angle is equidistant from both sides of the angle.

2 To a point equidistant from both sides of an angle, on the bisector of the angle.

3 Properties of bisectors of angles Theorem 1 and Theorem 2 are new ways to prove that angles are equal and line segments are equal. Theorem 1 is mostly used to prove that line segments are equal, and Theorem 2 is mostly used to prove that angles are equal or points are on angle bisectors.

Keywords: teaching courseware on the properties of angle bisectors, Qingdao edition eighth grade mathematics volume PPT courseware download, eighth grade mathematics slide courseware download, properties of angle bisectors PPT courseware download, .PPT format;

For more information about the "Properties of Angle Bisectors" PPT courseware, please click on the "Properties of Angle Bisectors" ppt tab.

"Properties of Angle Bisectors" PPT courseware:

"Properties of Angular Bisectors" PPT Courseware Scenario Introduction Tianquan Agricultural and Sideline Products Distribution Base M is located between the three villages of Lizhuang A, Wangzhuang B, and Zhaozhuang C. Its location is equidistant from the three highways AB, AC, and BC. Can you draw the position of M inside △ABC in the picture? Move...

"Properties of Angle Bisectors" Congruent Triangles PPT Courseware 2:

"Properties of Angle Bisectors" Congruent Triangles PPT Courseware 2 Observe and comprehend the practice, explore and think about the proof method: Practice: 1. With ____ as the center of the circle, the length of ______ as the radius, make an arc that intersects both sides of the angle at C respectively. , two points D; 2. With _____ as the center of the circle, ____..

"Properties of Angle Bisectors" Congruent Triangles PPT Courseware:

"Properties of Angle Bisectors" Congruent Triangles PPT Courseware 1. The concept of angle bisectors A ray divides an angle into two equal angles. This ray is called the bisector of the angle. 2. Distance from point to straight line: The length of the perpendicular segment from a point outside the straight line to the straight line.

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