"Solving linear equations of one variable" PPT courseware for linear equations of one variable 6

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"Solving linear equations of one variable" PPT courseware for linear equations of one variable 6

I believe you know how to ask for

1. When X takes what value, the value of the algebraic expression X-7 is 5?

2. Will the value of the algebraic expression 7x be equal to the value of the algebraic expression 6x-4?

We can use the equations we learned to solve:

1. X - 7 = 5

2. 7x = 6x - 4

Generally, after changing the sign of a term in an equation and moving it from one side of the equation to the other, this deformation is called a term shift.

Please tell me which type of deformation the following belongs to:

(1) From 3x-5+4x we get 3x+4x-5

(2) From 4x-5=3x, we get 4x-3x= 5

What new concepts did you learn in this class? What should we pay attention to? What problems will you learn to solve?

1. After changing the signs of the terms in the equation, move them from one side of the equation to the other side. This deformation is called moving terms. The number must be changed when moving items.

2. Learned how to solve linear equations of one variable containing parentheses. Its problem-solving procedure is: remove brackets ---- move terms ---- combine similar terms ---- divide both sides by the unknown coefficient.

What questions do you have?

1. What do you think is the best way to solve the following equations? Why? Will you choose wisely?

1. 4x+8=5x

2. 3(2x-1)=2(2x-1)+5

3. 5 - [ 2x- ( 3x+1 )] = 4

Solution: Move the terms and get 8=5x-4x. Combine similar terms and get 8 = x, that is, x=8

2. How to solve a linear equation of one variable with a denominator?

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Update Time: 2024-07-01

This template belongs to Mathematics courseware People's Education Press Seventh Grade Mathematics Volume 1 industry PPT template

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