"Ohm's Law" Ohm's Law PPT download (Lesson 2)

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"Ohm's Law" Ohm's Law PPT download (Lesson 2)

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"Ohm's Law" Ohm's Law PPT download (Lesson 2)

Part One: Knowledge Management

1. Laws related to series circuits

Current law: I=I1=I2

Voltage law: U=U1+U2

Resistance law: R= R1+R2

Voltage division rule: U1U2=R1R2

2. Laws related to parallel circuits

Current law: I=I1+I2

Voltage law: U= U1=U2

Resistance law: 1R=1R1+1R2

Diversion rule: I1I2=R2R1

Ohm's Law PPT, Part 2: Classification and Research

Type one: Series circuit related calculations

[2017•Suzhou, Jiangsu]In the circuit shown in Figure A, when the slider P moves from b to a, the voltage represents the change of the number U and the resistance R2 of the sliding varistor connected to the circuit. As shown in Figure B. Then the power supply voltage is 6 V; the resistance of resistor R1 is 10 Ω; when the slider P moves to the midpoint, the current through R1 is 0.3 A.

Type 2: Parallel circuit related calculations

[2018•Shandong Linyi]In the circuit as shown in the figure, R1=10 Ω.

(1) When only switch S1 is closed, the voltmeter reads 2.4 V. What is the ammeter reading?

(2) When switch S2 is closed again, the ammeter reads 0.4 A. What is the resistance of R2?

Ohm's Law PPT, Part 3: Assessment in class

1. [2018•Meishan, Sichuan]As shown in the figure, the power supply voltage remains unchanged. After closing the switch, both lamps can work normally. The ratio of the resistances of lamps L1 and L2 is R1:R2=1:2 , at this time, the ratio of the readings of the two ammeters A and B is ( D )

A. 2:1 B. 1:2

C. 3:2 D. 2:3

2. [2017•Shandong Linyi]In the circuit as shown in the figure, R1=15 Ω, R2=10 Ω, after closing the switch, the ammeter shows 0.3 A, then the power supply voltage is 3 V, passing The current in R1 is 0.2 A.

Ohm's Law PPT, Part 4: Layered Operations

1. [2018•Jiangsu Huaian]As shown in Figure A, it is the I-U image of the resistor R and the light bulb L. As can be seen from the figure, the resistance of resistor R is 10 Ω. Connect the resistor R and the light bulb L to the circuit in Figure B. After S is closed, the current is 0.3 A, and the power supply voltage is 4 V.

2. [2018•Jiangsu Taizhou]The picture shows the I-U image of resistors A and B. As can be seen from the figure: the resistance of resistor B is 10 Ω; connect resistors A and B in series and connect them to the circuit. When the current through A is 0.3 A, the total voltage across A and B is 4.5 V; connect resistors A and B After being connected in parallel and connected to a circuit, when the current through B is 0.2 A, the voltage across A is 2.0 V.

3. [2018•Xiangyang, Hubei]The I-U images of resistors R1 and R2 are as shown in the figure. When the voltage on R2 is 1.5 V, the resistance of R2 is 10 Ω; if they are connected in parallel to a power supply with a voltage of 2.5 V, the current of the main circuit is 0.7 A.

4. In the circuit shown in the figure, it is known that the power supply voltage is 9 V, the resistance of resistor R2 is 20 Ω, and the current after the switch S is closed is 0.3 A. beg:

(1) The indication of the voltmeter;

(2) R1 resistance;

(3) If R1 and R2 are connected in parallel to both ends of the power supply, find the main circuit current.

5. [2017•Sichuan Jiangyou]In the circuit as shown in the figure, the power supply voltage remains unchanged, the resistance of resistor R1 is 10 Ω, and the sliding rheostat R2 is marked with "5 Ω | 3 A". Close the switch S, and when the sliding plate P of the sliding rheostat moves to the right, there is one electric meter whose reading becomes larger; the difference between the readings of the voltmeter V and the reading of the voltmeter V1 and the ratio of the reading of the voltmeter V1 are less than (optional) "less than" "equal to" or "greater than")1.

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For more information about the PPT courseware "Ohm's Law and Ohm's Law Related Calculations", please click the Ohm's Law ppt Ohm's Law Related Calculations ppt tag.

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"Ohm's Law" Ohm's Law PPT download (Lesson 1) Part 1: Knowledge Management 1. Ohm's Law Content: The current in a conductor is directly proportional to the voltage across the conductor and inversely proportional to the resistance of the conductor. Formula: I=U/R. I current amperes (A), U..

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