"Skipping Rope" Addition and Subtraction PPT Courseware 2

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"Skipping Rope" Addition and Subtraction PPT Courseware 2

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"Skipping Rope" Addition and Subtraction PPT Courseware 2

How many more times does Xiaohong jump than Xiaoliang?

40-28=?

What should I do if there are no beads on the ones position?

One bead in the tens place is equivalent to 10 beads in the ones place.

Answer: Xiaohong jumps 12 times more than Xiaoliang.

Can you do the math in vertical form?

The 4 in the tenth place borrowed the 1, leaving 3.

Borrow 1 for 10

10-8=2

Subtracting 8 from 2 in the ones place is not enough, so borrow 1 from the tens place to make it 10.

3 on the tenth place is borrowed and 1 is left with 2

2-2=0

The highest bit 0 is not written

Summary

How to calculate two-digit subtraction and two-digit subtraction

1. Align the same digits.

2. Subtract from the single digit.

3. If the ones digit is not enough to subtract, retreat 1 from the tens digit, add 10 to the ones digit, and then subtract.

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For more information about the "Skipping Rope Addition and Subtraction" PPT courseware, please click the Skipping Rope Addition and Subtraction ppt tab.

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Update Time: 2024-07-05

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