"Solving linear equations of one variable" PPT courseware

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"Solving linear equations of one variable" PPT courseware

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"Solving linear equations of one variable" PPT courseware

Please judge

When Xiaogang was doing his homework, he encountered the equation 2x=5x. He divided both sides of the equation by x at the same time and got 2=5! Where did he go wrong?

What are the basic properties of the equation?

Solve the equation: 5x-2=8

Solution: Add 2 to both sides of the equation, we get

5x-2+2=8+2

5x=8+2

5x=10

x=2

Solve the equation 3x=2x+1

Solution: Subtract 2x from both sides of the equation at the same time to get

3x-2x=2x+1-2x

That is 3x-2x=1

Simplify and get x=1

what have you found?

After changing the sign of a term in the equation and moving it from one side of the equation to the other, this deformation is called moving the term.

Think about it: What is the basis for the transfer?

The basis for moving terms is the basic property of the equation 1

What should you pay attention to when moving items?

Please note when moving an item: the number of the moved item must be changed

Please judge

1. Is the following transfer correct? If it is wrong, how should it be corrected?

(1) From 5+x=10, we get x=10+5

(2) From 3x=8-2x, we get 3x+2x=-8

2. Is the solution to the following equation correct? If it is wrong, how should it be corrected?

Solve the equation -2x + 5=4 - 3x

Move the items and get 3x-2x=4+5

Combining similar terms, we get x=9

In-class exercises:

1. Solve the following equations and calculate orally to check

(1) 2.4x-2= 2x; (2) 3x+1 = -2

(3) 10x-3=7x+3 (4) 8-5x=x+2

2. Solve the following equations: (1) 2- 3(x-5)=2x;

(2) 4(4-y) =3(y-3);

(3) 2(2x-1)=1-(3-x);

(4) 2(x-1)- (3-x) = 2(1.5x-2.5)

Keywords: teaching courseware for solving linear equations in one variable, download the PPT courseware for seventh-grade mathematics volume 1 of Hebei Education Edition, download the slideshow courseware for seventh-grade mathematics, download PPT courseware for solving linear equations in one variable, .PPT format;

For more information about the PPT courseware "Solving Linear Equations of One Variable", please click on the "Solving Linear Equations of One Variable" PPT tab.

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 3):

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 3) Part 1: Knowledge points Basic knowledge point 1 Remove the denominator 1. Put the equation x-(x- 1)/2=2-(x+2)/ The correct denominator of 5 is (B) A.10x-5(x-1)=2-2(x+2) B.10x..

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2):

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2) Part 1: Knowledge points Basic knowledge point 1 Use brackets to solve linear equations of one variable 1. Set the equation 2x-4(2x-3)=6-2( x+1) The correct answer to removing the brackets is (D) A.2x-8x-12=6..

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 1):

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 1) Part 1: Knowledge points Basic knowledge point 1 Shifting terms 1. The basis of the rule of shifting terms when solving equations is (C) A. Commutative law of addition B. Addition Associative law C. Basic properties of equations 1 D. Etc..

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Update Time: 2024-10-03

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