"Solving linear equations of one variable" PPT of linear equations of one variable (Lesson 2)

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"Solving linear equations of one variable" PPT of linear equations of one variable (Lesson 2)

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"Solving linear equations of one variable" PPT of linear equations of one variable (Lesson 2)

Part One: Learning Objectives

1. Correctly master the method of shifting terms to find solutions to equations.

2. Steps to solve a linear equation of one variable using the term transfer method.

Solving linear equations of one variable PPT, part 2: independent learning feedback

Solve the following equations:

(1)3x-7(x-1)=3-2(x+3)

(2)3x-2[3(x-1)-2(x+2)]=3(18-x)

(1) Solution: remove the brackets and get: 3x-7x+7=3-2x-6

Move items and get: 3x-7x+2x=3-6-7

Combine similar items to get: -2x=-10

The coefficient is converted to 1: x=5

Solving linear equations of one variable PPT, the third part: new knowledge explanation

Xiaoying went to the supermarket to buy 1 can of fruit milk drink and 4 cans of Coke. The salesperson told her that a can of Coke cost 0.5 yuan more than a can of fruit milk drink. Xiaoying gave the salesperson 10 yuan, and the salesperson got 3 yuan back. Everyone helped. Xiaoying, how much does a can of fruit milk drink cost?

If a can of fruit milk drink costs x yuan, then the equation can be listed

4(x+0.5)+x=10-3

think about it

(1) Is the above equation correct? Can you also list different equations?

(2) How to solve the listed equations?

Do you know how much a can of fruit milk drink costs? Solve the equations you listed.

Example 3 Solve the equation: 4(x+0.5)+x=7.

How is this equation different from the equation learned in class?

The equation contains parentheses

The brackets must be removed first

What should I pay attention to when removing brackets?

bracket removal rule

There is a "+" sign before the bracket. Remove the bracket and the "+" sign before it, and the symbols of the items in the brackets will remain unchanged.

There is a "-" sign before the bracket. Remove the bracket and the "-" sign before it, and the sign of each item in the bracket will change.

Solving linear equations of one variable PPT, part 4: in-class testing

1.The solution of equation 2(x-1)+3=3x-1 is _______.

Analysis: Remove the brackets and get 2x-2+3=3x-1. Move the terms and combine similar terms to get -x=-2. Solve to get x=2. So fill in x=2.

2. When x=_______, the values ​​of algebraic expression 6+x and x+2 are opposite to each other.

Analysis: According to the meaning of the question, we get (6+x)+(x+2)=0. Remove the brackets and get 6+x+x+2=0. The solution is x=-4.

Therefore fill in -4.

3. Solve the equation 3x-7(x-1)=3-2(x+3) and remove the brackets to get___________.

4. Solve the following equations.

(1)2(x+8)=3(x-1); (2)8x=-2(x+4).

Solving linear equations of one variable PPT, Part 5: Apply what you have learned

A factory has strengthened energy-saving measures. Compared with the first half of last year, the average monthly electricity consumption decreased by 2,000 kilowatt-hours, and the annual electricity consumption was 150,000 kilowatt-hours. What was the average monthly electricity consumption of this factory in the first half of last year?

Analysis: If the average monthly electricity consumption in the first half of the year is x kilowatt-hours,

Then the average monthly electricity consumption in the second half of the year is _____________ kWh,

In the first half of the year, we shared _____ kilowatt hours of electricity.

In the second half of the year, the shared electricity consumption will be _______________ kilowatt hour.

Because a total of 150,000 kWh of electricity was used throughout the year,

Therefore, the equation can be written_____________________________.

Solving linear equations of one variable PPT, Part 6 content: Class summary

Steps to solve a linear equation of one variable with parentheses:

remove brackets

Move item

Merger of similar items

The coefficient is reduced to 1

Solving linear equations of one variable PPT, Part 7: Personalized homework

1. Complete the homework of Group A of 5.2.2 Solving linear equations of one variable.

2. Preview pages 140-141 of the textbook and complete the independent learning test questions in the next section.

1. Complete the homework of Group B in 5.2.2 Solving linear equations of one variable.

2. Preview pages 140-141 of the textbook and complete the independent learning test questions in the next section.

Keywords: Free download of Beijing Normal University version of seventh grade mathematics volume PPT courseware, PPT download of solving linear equations of one variable, PPT download of linear equations of one variable, .PPT format;

For more information about the PPT courseware "Solving a linear equation of one variable using a linear equation of one variable", please click the PPT tag of Solving a linear equation of one variable using a linear equation PPT.

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"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 3) Part 1: Knowledge points Basic knowledge point 1 Remove the denominator 1. Put the equation x-(x- 1)/2=2-(x+2)/ The correct denominator of 5 is (B) A.10x-5(x-1)=2-2(x+2) B.10x..

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2):

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 2) Part 1: Knowledge points Basic knowledge point 1 Use brackets to solve linear equations of one variable 1. Set the equation 2x-4(2x-3)=6-2( x+1) The correct answer to removing the brackets is (D) A.2x-8x-12=6..

"Solving linear equations of one variable" PPT download of linear equations of one variable (Lesson 1):

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