"Try and Guess" Mathematics Fun PPT

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"Try and Guess" Mathematics Fun PPT

Part One: Classroom Introduction

1. Students discover some special rules by observing and thinking about some phenomena in daily life.

2. Accumulate experience in solving problems through list enumeration, and go through the process of list, trial and continuous adjustment.

3. In real-life situations, students can feel the connection between the application of mathematical ideas and solving practical problems, and realize the value of mathematics.

Try and guess PPT, part 2: exploration of new knowledge

The breeding farm transports a batch of breeder chickens and rabbits, and due to constraints, they are kept in the same cage. When we arrived at the breeding farm, the breeder had to record the number of chickens and rabbits. Unexpectedly, the driver did not tell him directly, but asked him a question. Can you guess what the question was?

Chicken and rabbit in the same cage

Now there are pheasants and rabbits in the same cage. There are thirty-five heads on the top and ninety-four legs on the bottom. I want to ask how many pheasants and rabbits are there? ——The ancient Chinese mathematics masterpiece "Sun Tzu Suan Jing"

A chicken and a rabbit share a cage with 9 heads and 26 legs. How many chickens and rabbits are there?

Method 1: List

Method 2: Draw a picture

Method 3: Hypothesis

(1) Assume that the cage is full of chickens.

Total number of legs: 2×9=18 (pieces)

Less than actual: 26-18=8 (items)

1 chicken is less than 1 rabbit: 4-2=2 (rabbits)

Number of rabbits: 8÷2=4 (only)

Number of chickens: 9-4=5 (only)

(2) Suppose the cage is full of rabbits.

Total number of legs: 4×9=36 (pieces)

More than actual: 36-26=10 (items)

1 rabbit is more than 1 chicken: 4-2=2 (rabbits)

Number of chickens: 10÷2=5 (birds)

Number of rabbits: 9-5=4 (only)

Try and Guess PPT, Part 3: Class Summary

Solution to the problem of chickens and rabbits living in the same cage:

1. List method: First assume how many animals there are, then calculate the number of another animal based on the total number of heads, and then calculate whether the total number of legs is consistent with the meaning of the question.

2. Drawing method: first assume that they are all of a certain kind of animal, then remove or add the number of legs that are more or less drawn, and draw a conclusion.

3. Hypothesis: Also pretend to be a certain kind of animal first, and use calculations to express the drawing process.

Try and Guess PPT, Part 4: Classwork

1. There are 27 coins of 1 jiao and 5 jiao in Lele's piggy bank. The total is 5.1 yuan. How many coins of 1 jiao and 5 jiao are there?

Answer: There are 21 1-cent coins and 6 5-cent coins.

2. There are 22 tricycles and bicycles in the parking lot, with 59 wheels. How many bicycles and tricycles are there?

Suppose the parking lot is full of bicycles.

Tricycle: (59-22×2)÷(3-2)

=(59-44)÷1

=15÷1

=15 (vehicles)

Bicycles: 22-15=7 (vehicles)

Answer: There are 7 bicycles and 15 tricycles.

Keywords: Free download of Beijing Normal University Edition fifth grade mathematics PPT courseware, first volume, try and guess PPT download, fun mathematics PPT download, .PPT format;

For more information about the PPT courseware "Mathematics Fun Trying and Guessing", please click the Fun Mathematics PPT Trying and Guessing PPT tab.

"Try and Guess" Mathematics Fun PPT Download:

"Try and Guess" Mathematics Fun PPT Download Part One: Knowledge Explanation A chicken and a rabbit in the same cage have 9 heads and 26 legs. How many chickens and rabbits are there? I have long heard about the problem of chickens and rabbits living in the same cage, but I just don’t know how to do it. What are the possibilities with 9 heads? List to try. ..

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Update Time: 2024-09-15

This template belongs to Mathematics courseware Beijing Normal University Edition Fifth Grade Mathematics Volume 1 industry PPT template

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